[An old proof. “By finding scaled versions of the triangle within itself”. Yet somewhat mysterious.]
So ${c = ( \frac{b}{c} ) b + ( \frac{a}{c} ) a. }$
[An old proof. “By finding scaled versions of the triangle within itself”. Yet somewhat mysterious.]
So ${c = ( \frac{b}{c} ) b + ( \frac{a}{c} ) a. }$